0=x^2-4x-270

Solution for 0=x^2-4x-270 equation:

0=x^2-4x-270

We move all terms to the left:

0-(x^2-4x-270)=0

We add all the numbers together, and all the variables

-(x^2-4x-270)=0

We get rid of parentheses

-x^2+4x+270=0

We add all the numbers together, and all the variables

-1x^2+4x+270=0

a = -1; b = 4; c = +270;
Δ = b2-4ac
Δ = 42-4·(-1)·270
Δ = 1096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1096}=\sqrt{4*274}=\sqrt{4}*\sqrt{274}=2\sqrt{274}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{274}}{2*-1}=\frac{-4-2\sqrt{274}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{274}}{2*-1}=\frac{-4+2\sqrt{274}}{-2}
$